(x^2-2x)^2+5(x^2-2x)+4=0

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Solution for (x^2-2x)^2+5(x^2-2x)+4=0 equation: 



(x^2-2x)^2+5(x^2-2x)+4=0

We multiply parentheses

5x^2+(x^2-2x)^2-10x+4=0

We add all the numbers together, and all the variables

5x^2-10x+(x^2-2x)^2+4=0

We move all terms containing x to the left, all other terms to the right

5x^2-10x+(x^2-2x)^2=-4

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